The points a 2 9 b a 5 and c 5 5
Webb16 mars 2024 · Ex 4.3, 2 (Introduction) Show that points A (a , b + c), B (b,c + a), C (c,a + b) are collinear 3 points collinear Area of triangle = 0 Area of triangle ≠ 0 Ex 4.3, 2 Show that points A (a , b + c), B (b, c + a), C (c,a + b) are collinear Three … Webb29 mars 2024 · Transcript. Example 12 Find the area of a triangle formed by the points A(5, 2), B(4, 7) and C (7, – 4). Area of triangle ABC = 1/2 [ x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2) ] Here x1 = 5 , y1 = 2 x2 = 4 , y2 = 7 x3 = 7 , y3 = −4 Putting values Area of triangle ABC = 1/2 [ 5(7 – (−4)) + 4(−4 – 2 ) + 7(2 − 7) ] = 1/2 [ 5(7 + 4) + 4(−6 ) + 7(−5) ] = 1/2 [ 5(11) + 4(−6 ...
The points a 2 9 b a 5 and c 5 5
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Webb20 juni 2024 · If the points A(-1, 3, 2), B(-4, 2, -2) and C(5, 5, λ) are collinear then the value of λ is A. 5 B. 7 C. 8 D. 10 asked Aug 13, 2024 in Straight Lines by Jagat ( 41.5k points) … WebbThe points A(2,9),B(a,5) and C(5,5) are the vertices of a triangle ABC right angled at B. Find the values of a and hence the area of Δ ABC. A a=−1 , Area = 15 sq. unit B a=2 , Area = 6 …
WebbIf the points A(2,9), B(a,5) and C(5,5) are the vertices of a Δ ABC right angled at B, then find the values of a and hence the area of Δ ABC. Q. The point A ( 2 , 3 ) , B ( 4 , − 1 ) , C ( − 1 , … Webb22 mars 2024 · Three points A, B, C are collinear if direction ratios of AB and BC are proportional. AB A (2, 3, −4) B (1, −2, 3) Direction ratios = 1 − 2, −2 − 3, 3 − (−4) = −1, −5, 7 …
Webb8 dec. 2024 · The points A (2,9) B (k,5)and C (5,5) are the vertices of triangle ABC right angled at B.find the values of K and hence the area of triangle. Advertisement Loved by … Webb10 okt. 2024 · If the distance between the points ( mathrm A (a 2) ) and ( mathrm B (3 5) ) is ( sqrt 53 ) find the possible values of ( a ) - Given:The distance between the points ( mathrm{A}(a, 2 ... The points ( mathrm{A}(2,9), mathrm{B}(a, 5) ) and ( mathrm{C}(5,5) ) are the vertices of a triangle ( mathrm{ABC} ) right angled at ( mathrm{B ...
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